Question

Y=x^2cos(x)/sin(x) find dy/dx ? pls help

Answer 1

`=-x^2csc^2x+2xcotx`

Explanation:

According to socratic format your question is:

`y=x^2cosx/sinx`

`y=x^2cotx`

`=>(dy)/(dx)=x^2d/(dx)(cotx)+cotxd/(dx)(x^2)`

`=x^2(-csc^2x)+cotx(2x)`

`=-x^2csc^2x+2xcotx`

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