Y=x^2cos(x)/sin(x) find dy/dx ? pls help

1 Answer
Mar 29, 2018

=-x^2csc^2x+2xcotx

Explanation:

According to socratic format your question is:

y=x^2cosx/sinx

y=x^2cotx

=>(dy)/(dx)=x^2d/(dx)(cotx)+cotxd/(dx)(x^2)

=x^2(-csc^2x)+cotx(2x)

=-x^2csc^2x+2xcotx

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