What is the standard form of #y= (3x – 4) (2x – 1) (x – 2)#?

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Answer 1 · 2018-03-30T10:23:16

#y=6x^3-23x^2+26x-32/3#

#y=(3x-4)(2x-1)(x-2)#

#=3xx2xx1xx(x-4/3)(x-1/2)(x-2)#

#=6(x^3-(4/3+1/2+2)x^2+(4/3xx1/2+1/2xx2+2xx4/3)x-4/3xx1/2xx2)#

#4/3+1/2+2=(8/6+3/6+12/6)=(8+3+12)/6=23/6=69/18#

#4/3xx1/2+1/2xx2+2xx4/3=2/3+1+8/3=2/3+3/3+8/3#
#=(2+3+8)/3=13/3=26/6=78/18#

#4/3xx2/3xx2=(4xx2xx2)/(3xx3)=16/9=32/18#

#(3x-4)(2x-1)(x-2)=6(x^3-69/18x^2++78/18x-32/18)#

#y=6x^3-23x^2+26x-32/3#