What is the slope of a line tangent to the curve #3y^2-2x^2=1#?
1 Answer
Mar 30, 2018
The slope of the tangent line is
Explanation:
We have:
#6y(dy/dx) - 4x = 0#
#6y(dy/dx) = 4x#
#dy/dx= (4x)/(6y)#
#dy/dx = (2x)/(3y)#
Hopefully this helps!
