How do you solve #\frac { 1} { 2} x + 5\leq 8#?

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Answer 1 · 2018-03-30T19:08:08

#1/2x+5<=8#

#rArrx<=6#

The algebraic rules for solving inequalities are almost exactly the same as for solving equations.

#1/2x+5<=8#

#rArr1/2x+cancel5-cancelcolor(red)5<=8-color(red)(5)#

#rArr1/2x<=3#

#rArrcancelcolor(red)2*1/cancel2x<=color(red)2*3#

#rArrx<=6#