Mechanics question help ?
A force of 6i+j N acts on a particle of mass 2 kg. The initial velocity of the particle is 2i−5j ms-1.
The velocity of the particle after 4 seconds is _i + ____j ms-1.
A force of 6i+j N acts on a particle of mass 2 kg. The initial velocity of the particle is 2i−5j ms-1.
The velocity of the particle after 4 seconds is _i + ____j ms-1.
2 Answers
See below.
Explanation:
integrating once
but
Explanation:
Force on particle is
#"F" = (6hati + hatj)\ "N"#
Acceleration of particle is
#"a" = "F"/"m" = ((6hati + hatj)\ "N")/"2 kg" = (3hati + 0.5hatj)\ "m/s"^2#
Velocity of particle after
#"v = u + at"#
#"v" = [(2hati - 5hatj)\ "m/s"] + [(3hati + 0.5hatj)\ "m/s"^cancel(2) × 4 cancel"s"]#
#"v" = (2hati - 5hatj)\ "m/s" + (12hati + 2hatj)\ "m/s"#
#"v" = (14hati - 3hatj)\ "m/s"#