How do you simplify $(4 + \sqrt{50}) - (3 - \sqrt{8})$ $(4+sqrt50)-(3-sqrt(8))$ ?

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Answer 1 · 2018-03-31T13:33:00

$= 1 + 7 \sqrt{2}$ $=1+7sqrt2$

$\sqrt{50} = 5 \sqrt{2}$ $sqrt50=5sqrt2$ and $\sqrt{8} = 2 \sqrt{2}$ $sqrt8=2sqrt2$

Equation becomes $(4 + 5 \sqrt{2}) - (3 - 2 \sqrt{2})$ $(4+5sqrt2)-(3-2sqrt2)$

$= 4 + 5 \sqrt{2} - 3 + 2 \sqrt{2}$ $=4+5sqrt2-3+2sqrt2$

$= 1 + 7 \sqrt{2}$ $=1+7sqrt2$

Answer 2 · 2018-03-31T13:33:45

$(4 + \sqrt{50}) - (3 - \sqrt{8}) = 1 + 7 \sqrt{2}$ $(4+sqrt50)-(3-sqrt8)=1+7sqrt2$

$(4 + \sqrt{50}) - (3 - \sqrt{8})$ $(4+sqrt50)-(3-sqrt8)$

$\sqrt{50} = \sqrt{25 \times 2} = \sqrt{25} \times \sqrt{2} = 5 \sqrt{2}$ $sqrt50=sqrt(25xx2)=sqrt25xxsqrt2=5sqrt2$

$\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}$ $sqrt8=sqrt(4xx2)=sqrt4xxsqrt2=2sqrt2$

$(4 + \sqrt{50}) - (3 - \sqrt{8}) = (4 + 5 \sqrt{2}) - (3 - 2 \sqrt{2})$ $(4+sqrt50)-(3-sqrt8)=(4+5sqrt2)-(3-2sqrt2)$

$= 4 + 5 \sqrt{2} - 3 + 2 \sqrt{2}$ $=4+5sqrt2-3+2sqrt2$

$= (4 - 3) + (5 \sqrt{2} + 2 \sqrt{2})$ $=(4-3)+(5sqrt2+2sqrt2)$

$= 1 + 7 \sqrt{2}$ $=1+7sqrt2$

$(4 + \sqrt{50}) - (3 - \sqrt{8}) = 1 + 7 \sqrt{2}$ $(4+sqrt50)-(3-sqrt8)=1+7sqrt2$

How do you simplify (4+√50)−(3−√8)(4+sqrt50)-(3-sqrt(8)) ?