How do you solve log(2x-8)=4?

1 Answer
Mar 31, 2018

x={e^4+8}/2 approx 31.3

Explanation:

(Assuming log base e)

The trick is to rewrite 4 as a logarithm so that the logarithms can be removed. 4=log(e^4)

log(2x-8)=4

log(2x-8)=log(e^4)
2x-8=e^4

2x=e^4+8

x={e^4+8}/2 approx 31.3