Immediate. Immediate. Please help with limit problem?
3 Answers
Mar 31, 2018
Explanation:
We want to solve
lim_(x->0)(e^x-e^-x)/x
This leads to an indeterminate form
therefore we can apply L'Hôpital's rule
color(blue)(lim_(x->a)f(x)/g(x)=lim_(x->a)(f'(x))/(g'(x))
Thus
lim_(x->0)(e^x-e^-x)/x=lim_(x->0)(e^x+e^-x)/1=2
Mar 31, 2018
Explanation:
and
then
then
Apr 1, 2018
Image....
Explanation:
my notebook..
Without L Hospital rule...