How do you find the x and y intercept for #2x+6y=-12#?

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Answer 1 · 2018-04-01T05:07:24

x- intercept #(-6,0)#
y-intercept #(0,-2)#

Given -

#2x+6y=-12#

To find the x-intercept put #y=0#

#2x+6(0)=-12#

#2x=-12#

#x=(-12)/2=-6#

x- intercept #(-6,0)#

To find the y-intercept put #x=0#

#2(0)+6y=-12#

#6y=-12#

#y=(-12)/6=-2#

y-intercept #(0,-2)#