Could someone help me evaluate this another limit?

lim _(x->oo) (root(2)(x+1) -root(2)(x-1))/ x

1 Answer
Apr 1, 2018

0

Explanation:

(root(2)(x+1) -root(2)(x-1))/ x =( (x+1)-(x-1))/(x(root(2)(x+1) +root(2)(x-1))) = 2/(x(root(2)(x+1) +root(2)(x-1))) then

lim_(x->oo)(root(2)(x+1) -root(2)(x-1))/ x = 0