How do you simplify #\frac { k ^ { 2} - 12k + 32} { k ^ { 2} - 64 }#?

1 Answer
Apr 1, 2018

#=> (k-4)/(k+8 ) #

Explanation:

Use factorisation:

#=> ((k-8)(k-4) )/ (k^2 -64 ) #

Use difference in two squares:

#a^2 - b^2 = (a-b)(a+b) #

#=> ( (k-8)(k-4) ) / ( (k-8)(k+8) #

Cancel down:

#=> ( cancel((k-8))(k-4) ) / ( cancel((k-8))(k+8) #

#=> (k-4)/(k+8 ) #