An object with volume 6.0*10^1 m^3 and mass of 2.600*10^4 kg will have bouyancy force,in ethyl alcohol?

2 Answers
Mar 31, 2018

the force of buoyancy = mass of the bodyx g=2.6 x 10^4 kg-wt

Explanation:

the ethyl alcohol has density = 0.789gml=789(kgm3)

the volume of the body is 60m3 which will naturally float on the liquid with a part of it submerged in the liquid.

the volume of the displaced liquid say V1
will provide the necessary buoyant force to support the wt. of the body
therefore #V1. density . g = mass . g

where g is acceleration due to gravity.

therefore the force upward = 2.6.104.g=2.6. 105 N
here g=10ms2

if one estimates volume of the liquid displaced it will come to about 32.9m3

it means almost half of the body will be above ethanol.

Apr 1, 2018

The buoyancy force is 2.55105N upward.

Explanation:

The density of the object is 2.6104kg60m3=433.3kgm3.
From a table of densities, the density of ethyl alcohol is 789kgm3, which is greater than that of the object.

Therefore the object will float. The object still has weight, a downward force, given by

mg=2.6104kg9.8ms2=2.55105N.

Since it is in equilibrium at the top of the ethyl alcohol, the buoyancy force must be an equal and opposite force. Therefore, the buoyancy force is 2.55105N upward.

I hope this helps,
Steve