How do you simplify #(r+6)/(6+r)#?

4 Answers
Apr 1, 2018

#(r+6)/(6+r)=1#

Explanation:

addition is commutative, so :
#r+6=6+r#, and trivially you have #(r+6)/(6+r)=1#

Apr 1, 2018

#1#

Explanation:

Think about it: #r+ 6 = 6 + r#

Therefore, the numerator and the denominator can cancel each other out to have a total value of #1#.

Apr 1, 2018

See explanation.

Explanation:

Since rhe result of addition does not depend on the order of operands we can write that:

#r+6=6+r#

Knowing that we can write that:

#(r+6)/(6+r)=(r+6)/(r+6)=1# ##

The above equality is true for all #x# for which the value is defined, i.e. for all real values other than #r=-6#.

Apr 1, 2018

#1#

Explanation:

We have the same thing on the numerator and the same thing on the denominator, thus this expression is equal to #1#.

#r+6# is the same as #6+r#, because addition is commutative. Thus, we would have:

#(r+6)/(r+6)#

The terms would cancel with each other, and we would essentially be left with a #1#. We can view this as the coefficient on the #r# term.

In general, #a/a=1#. So if the top and bottom of a fraction is the same, it is equal to #1#.

Hope this helps!