What is the equation of a line that passes through the points #(-0.72, 1.42)# and #(4.22, 5.83)#?

1 Answer
Mark D.
Apr 3, 2018

#y=(4.41/4.94)x+2.06#

Explanation:

#(5.83-1.42)/(4.22--0.72)# =#4.41/4.94# this is the gradient

#y=(4.41/4.94)x +c# put in the values from one of the points

Using (4.22,5.83) #=># #5.83=(4.41/4.94)##xx#4.22 + c

#=># #5.83=3.767246964 + c#

c=2.0627530364372

#y=(4.41/4.94)x+2.06#

Related questions
Impact of this question
1542 views around the world
You can reuse this answer
Creative Commons License