How do you solve #9(x+2)= 5[11-2(2-x)+3]#?

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Answer 1 · 2018-04-04T02:49:24

#color(maroon)(x = - 32#

#9(x+20 = 5 [11 - 2(2 -x) + 3]#

#9(x+2) = 5 * 11 - 5 * 2 * (2 - x) + 5 * 3, color(blue)(" removing [ ] bracket"#

#9x + 18 = 55 - 20 + 10x + 15, color(green)(" Removing () braces "#

#9x - 10x = 55 - 20 + 15 - 18. color(crimson)(" bringing like terms together"#

#-x = 70 - 38 = 32#

#color(maroon)(x = - 32#

Answer 2 · 2018-04-04T02:53:40

#x = -32#

#9(x+2) = 5[11-2(2-x)+3]#

Expand and Simplify Both Sides (Following Bedmas)

#9x+18 = 5[11-4+2x+3]#

#9x+18 = 5[10+2x]#

#9x+18 = 50+10x#

Isolate for #x#

#18 - 50 = 10x - 9x#

#-32 = x#