How do you differentiate the following parametric equation: # x(t)=lnt-t, y(t)= tcos^2t #?
1 Answer
Apr 4, 2018
Find the derivative of the
#x'(t) = 1/t - 1#
#y'(t) = 1(cos^2t) - tsintcost = cos^2t - tsintcost#
Therefore
#dy/dx = (cos^2t - 2tsintcost)/((1 -t)/t)#
#dy/dx= (tcos^2t - 2t^2sintcost)/(1 - t)#
Hopefully this helps!
