What are the solution in the interval [0, 2pie]? sec^2x-tan^2x=0
1 Answer
Apr 4, 2018
See explanation
Explanation:
We want to solve the equation
sec^2(x)-tan^2(x)=0
To get a better idea, write this in terms of sine and cosine
1/cos^2(x)-sin^2(x)/cos^2(x)=0
To simplify multiply both sides by
1-sin^2(x)=0
Thus
sin^2(x)=1
=>sin(x)=+-sqrt(1)
=>sin(x)=+-1
Now i will leave it for you to find the solutions