How do you factor the expression #13c^2 - 52#? Algebra Polynomials and Factoring Factoring Completely 1 Answer sankarankalyanam Apr 4, 2018 #color(brown)(=> 13 * (c + 2 ) * (c - 2))# Explanation: #13c^2 - 52 = 13c^2 - 13 * 4 # #=> 13 (c^2 - 4), " taking common term out"# #color(brown)(=> 13 * (c + 2 ) * (c - 2)) " as " a^2 - b^2 = (a = b) (a - b)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1366 views around the world You can reuse this answer Creative Commons License