Question

Please answer?

Answer 1

`y=4-x`

Explanation:

`y=x/20(x^2-10)`
`y=x^3/20-x/2`
`y=(x^3-10x)/20`

Here, you will notice that the equation resembles some part of the equation: `x^3+10x-80=0`

SO basically, you have to think of an equation that can get you an `80` and somehow get you a `+10x`
ie `20times (some value)` gets you an `80` and `+10x`

so the line `y=4-x` will get you that

`4-x=(x^3-10x)/20`
`80-20x=x^3-10x`
`x^3+10x-80=0`