How do you solve #-2\leq \frac { 1+ p } { 2}#?

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Answer 1 · 2018-04-05T14:20:42

#-2 <= (1+p)/2#

isolate #p#

#-4 <= 1+p#

#-4 -1 <=p#

#-5 <=p#

Answer 2 · 2018-04-05T14:25:19

#-5<=p#

Multiply both sides by #2#
#-2 xx2<=((1+p) /2)xx2#

#=-4<=1+p#

Subtract both sides by #1#

#=-4-1<=1-1+p#

Simplify

#=-5<=p#

[Although it's usually preferred to have your "numbers" on the left... But don't forget to switch your sign around if you do so!]

#p>=-5#