How do you simplify #sqrt(35) xx sqrt(15)#?

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Answer 1 · 2018-04-05T19:15:59

#5sqrt(21)#

You can 'split' roots

#sqrt(5xx7)xxsqrt(3xx5)#

#sqrt5xxsqrt7xxsqrt3xxsqrt5#

#sqrt5xxsqrt5xxsqrt(3xx7)#

#5sqrt(21)#
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Lets test this approach with numbers we know

#sqrt(16)=4" "# Technically it is #+-4# but lets ignore that.

#sqrt(4xx4) = sqrt(4)xxsqrt(4) = 2xx2 =4#