Which is the limit of sin^2x/x?

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Answer 1 · 2018-04-06T23:22:13

=0

#lim_(x->0) (sin^2x)/x#

----#lim_(x->0) (sinx)/x=1#

multiply by

#lim_(x->0) (sinx.sinx)/x=lim_(x->0) (x)/x(sinx.sinx)/x#

#lim_(x->0) (x)/x(sinx.sinx)/x=lim_(x->0)x((sinx.sinx))/(x.x)=lim_(x->0)(sinx/x)(sinx/x)(x)#

#lim_(x->0)(sinx/x)(sinx/x)(x)=1.1.x=x#

#lim_(x->0) (sin^2x)/x=lim_(x->0) x#

#lim_(x->0) x=0#