What is the equation of the circle with a center at #(2 ,5 )# and a radius of #6 #?

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Answer 1 · 2018-04-07T04:16:39

#(x-2)^2+(y-5)^2=36#

The standard equation of a circle with center at #(h,k)# and radius #r# is given by

#(x-h)^2+(y-k)^2=r^2.# We're given #(h,k)=(2,5), r=6#

So, the equation is

#(x-2)^2+(y-5)^2=6^2#

#(x-2)^2+(y-5)^2=36#