How do you solve #abs(4x+10)<20#?
1 Answer
Apr 7, 2018
Explanation:
#"inequalities of the type "|x| < a#
#"always have solutions of the form"#
#-a < x < a#
#rArr-20<4x+10<20#
#"subtract 10 from each interval"#
#-20color(red)(-10)>4xcancel(+10)cancel(color(red)(-10))20color(red)(-10)#
#rArr-30<4x <10#
#"divide each interval by 4"#
#-30/4 < x<10/4#
#rArr-15/2 < x < 5/2#
#x in(-15/2,5/2)larrcolor(blue)"in interval notation"#
