How do you solve #10x^2-56=88-6x^2#?

2 Answers
SourLemonn8
Apr 7, 2018

#x=+-3#

Explanation:

#10x^2-56=88-6x^2#
#10x^2+6x^2=88+56#
#16x^2=144#
#x^2=9#
#x=sqrt(9)#
#x=+-3#

Jim G.
Apr 7, 2018

#x=+-3#

Explanation:

#"rearrange the equation with terms in "x^2" on the left"#
#"side and numeric values on the right side"#

#rArr16x^2=144#

#"divide both sides by 16"#

#rArrx^2=144/16=9#

#color(blue)"take the square root of both sides"#

#rArrx=+-sqrt9larrcolor(blue)"note plus or minus"#

#rArrx=+-3#

Related questions
Impact of this question
1919 views around the world
You can reuse this answer
Creative Commons License