How much power is produced if a voltage of #5 V# is applied to a circuit with a resistance of #96 Omega#?

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Answer 1 · 2018-04-07T18:41:45

The power is approximately #0.26# Watts

Let #I=# current, #P=# power, #V=# voltage, and #R=# resistance.

Ohm's law states

#V=IR#

We can solve this for current.

#I=V/R#

We also know that

#P=IV#.

We can eliminate the current with Ohm's Law.

#P=V^2/R=5^2/96~~0.26# Watts

Answer 2 · 2018-04-08T01:51:39

Around #0.26# watts

Ohm's law states that,

#V=IR#

#I# is the current in amperes

#R# is the resistance in ohms

#<=>I=V/R#

Meanwhile, power is measured through,

#P=IV#

#V# is the voltage in volts

#<=>I=P/V#

Through the two equations, we get a relationship:

#V/R=P/V#

#P=V^2/R#

Now, we can simply plug in the values, and get:

#P=(5 \ "V")^2/(96 \ Omega)#

#=(25 \ "V"^2)/(96 \ Omega)#

#~~0.26 \ "W"#