How do you simplify $(p^{5} r^{4}) (p^{2} r)$ $(p^5r^4)(p^2r)$ ?

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Answer 1 · 2018-04-08T08:46:25

Expression $= p^{7} r^{5}$ $= p^7r^5$

Here we will use the law of exponents: $a^{m} \times a^{n} = a^{m + n}$ $a^m xx a^n = a^(m+n)$

Expression $= (p^{5} r^{4}) (p^{2} r)$ $= (p^5r^4)(p^2r)$

$= p^{5} \times r^{4} \times p^{2} \times r^{1}$ $= p^5xxr^4xxp^2xxr^1$

$= p^{5} \times p^{2} \times r^{4} \times r^{1}$ $= p^5xxp^2 xx r^4xxr^1$

$= p^{5 + 2} \times r^{4 + 1}$ $= p^(5+2) xx r^(4+1)$

$= p^{7} r^{5}$ $= p^7r^5$

How do you simplify (p5r4)(p2r)(p^5r^4)(p^2r)?