How many grams is 5.72 * 10^21 atoms of Li?

1 Answer
Apr 8, 2018

2.067*10^46 gm

Explanation:

firstly, we have to calculate no. of moles
i.e. no. of moles = no. of atoms * N_A(Avagadro's Number)
no. of moles = 5.72*10^21*6.023*10^23
no. of moles = 34.45*10^44=3.445*10^45
mass of Li = molar mass * no. of moles
=6*3.445*10^45=2.067*10^46 gm