Question

What is the axis of symmetry of the parabola with the equation `x-4=1/4(y+1)^2`?

Answer 1

Axis of symmetry is `y+1=0`

Explanation:

If the equation of parabola is of the form `y=a(x-h)^2+k`, axis of symmetry is `x-h=0` or `x=h`

and if the equation of parabola is of the form `x=a(y-k)^2+h`, axis of symmetry is `y-k=0` or `y=k`.

We can write `x-4=1/4(y+1)^2` i.e.

`x=1/4(y+1)^2+4` and

and axis of symmetry is `y+1=0`