What is the slope of any line perpendicular to the line passing through (3,8)(3,8) and (20,-5)(20,5)?

2 Answers
Apr 9, 2018

17/131713

Explanation:

First let's find the slope of the line passing through the aforementioned points.

(y_2-y_1)/(x_2-x_1) rarry2y1x2x1 Finding the slope using two points

(-5-8)/(20-3)58203

-13/17 rarr1317 This is the slope

Perpendicular slopes are opposite reciprocals of one another.

Opposites: -2 and 2, 4 and -4, -18 and 18, etc.

Add a negative sign to the front of any number to find its negative.

-(-13/17)=13/17(1317)=1317

To make something a reciprocal of another number, flip the numerator and denominator of the original number.

13/17 rarr 17/1313171713

Apr 9, 2018

m = 17/13m=1713

Explanation:

First, find the slope of this line by using this formula:

m = (y_2-y_1)/(x_2-x_1)m=y2y1x2x1

Now you choose which point has y_2y2 and x_2x2 and which point has y_1y1 and x_1x1

y_2 = 8y2=8 and x_2 = 3x2=3
y_1 = -5y1=5 and x_1 = 20x1=20

Now plug into the formula to get:

m = (8-(-5))/(3-20)m=8(5)320

m = (8+5)/(3-20)m=8+5320

m = 13/(-17)m=1317

m = -13/(17)m=1317

Now that we have found the slope of the first line we can find the slope of any line perpendicular to it. To do this you have to find the slope's opposite reciprocal. To do this just flip the fraction (change the numerator and denominator) and put a negative sign in front.

So the slope of any line perpendicular is

m = 17/13m=1713