Question

What the is the polar form of `y^2 = (x-1)^2/(y+x)-x^2`?

Answer 1

Let `x = rcos(theta)` and `y = rsin(theta)`

Explanation:

`r^2sin^2(theta) = (rcos(theta)-1)^2/(rsin(theta)+rcos(theta)) - r^2cos^2(theta)`
`r^2(sin^2(theta)+cos^2(theta)) = (rcos(theta)-1)^2/(rsin(theta)+rcos(theta)`
`r^3 = (rcos(theta)-1)^2/(sin(theta)+cos(theta))`

I don't think the expression simplifies further.