What the is the polar form of y^2 = (x-1)^2/(y+x)-x^2 ?

1 Answer
Apr 9, 2018

Let x = rcos(theta) and y = rsin(theta)

Explanation:

r^2sin^2(theta) = (rcos(theta)-1)^2/(rsin(theta)+rcos(theta)) - r^2cos^2(theta)
r^2(sin^2(theta)+cos^2(theta)) = (rcos(theta)-1)^2/(rsin(theta)+rcos(theta)
r^3 = (rcos(theta)-1)^2/(sin(theta)+cos(theta))

I don't think the expression simplifies further.