Calculate the pH of 0.0070 M butanoic acid, which is a monoprotic acid; Ka=1.52 x 10−5. Assume that the 5% approximation rule applies. Provide your answer to two places after the decimal?
1 Answer
Explanation:
Butanoic acid (
DISSOCIATION
The equilibrium constant for this expression is called the acid dissociation constant, Ka.
The expression for Ka is:
AT EQUILIBRIUM
Write each equilibrium concentration in terms of x
So,
With the small x approximation,
Calculating,
NOTES
Checking the 5% Rule (not used in here)