Question

How do you convert `-3 – 6i` to polar form?

Answer 1

To convert to polar form we need to find modulus and argument of `-3 - 6i`

Explanation:

Modulus:
`|\-3-6i| = sqrt((-3)^2+(-6)^2)`
`|\-3-6i| = sqrt(45)`

Argument:
`theta = tan^-1(6/3)`
`theta = tan^-1(2)`

Then `-3-6i` can be rewritten as
`sqrt(45)(cos(tan^-1(2))+isin(tan^-1(2)))`

or

`sqrt(45)cis(tan^-1(2))`