What is the moment of inertia of a pendulum with a mass of #3 kg# that is #3 m# from the pivot?

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Answer 1 · 2018-04-10T12:26:56

#27 \ "kg m"^2#

The moment of inertia of a simple pendulum is given by:

#I=mr^2#

#m# is the mass of the bob in kilograms

#r# is the distance of the bob from the pivot in meters

And so, we get:

#I=3 \ "kg"*(3 \ "m")^2#

#=3 \ "kg"*9 \ "m"^2#

#=27 \ "kg m"^2#