A circle's center is at (2 ,1 ) and it passes through (3 ,2 ). What is the length of an arc covering (7pi ) /12 radians on the circle?

1 Answer
Apr 12, 2018

arc length=(11sqrt(2))/6 units

Explanation:

Let A(2,1) be the center of the circle and B(3,2) be the arc length.

Now, radius of circle=AB=sqrt((3-2)^2+(2-1)^2)=sqrt(2)

rarrtheta=arc length/(radius

rarr=(7pi)/12=l/sqrt2

rarr7*(22/7)*1/12=l/sqrt(2)

rarrl=(11sqrt2)/6 units