Question

How do you calculate `log_5 (18)`?

Answer 1

`log_5 18=1.7959`

Explanation:

Let `log_nm=x`

then `n^x=m` and taking log to the base `10` on each side

`xlogn=logm` i.e. `x=logm/logn`

i.e. we can write `log_nm=logm/logn`

or `log_5 18=log18/log5=1.2553/0.6990=1.7959`