How do you write #2 +4i# in trigonometric form?
1 Answer
Apr 12, 2018
Explanation:
#"to convert to trigonometric form"#
#"that is "x+yitor(costheta+isintheta)" using"#
#•color(white)(x)r=sqrt(x^2+y^2)#
#•color(white)(x)theta=tan^-1(y/x);-pi < theta <=pi#
#"here "x=2" and "y=4#
#rArrr=sqrt(2^2+4^2)=sqrt20=2sqrt5#
#theta=tan^-1(2)=1.107" radians to 3 dec. places"#
#rArr2+4i=2sqrt5(cos(1.107)+isin(1.107))#
