How do you simplify #(-4x)/12 ( 121x+22)#?

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Answer 1 · 2018-04-12T12:10:48

By arranging the equation

#(-4x)/12 times (121x+22)#

#=(-4x)/(4times3)times(121x+22)#

#-x/3times(121x+22)#

#=(-121x^2-22x)/3#

Your answer is

#=(-121x^2-22x)/3#

Answer 2 · 2018-04-12T12:13:31

#-(11x(11x+2))/3#

Firstly we can see that #-(4x)/12# (#larr# we can put the negative sign like that) can be simplified.

#-cancel(4x)/cancel12# (divide them both with 4 because it's common to both numbers) turns into #-x/3#

Now we have #-x/3 (121x +22)#

The next thing we do is multiply #x# with #(121x +22)# , and we get:

#(x(121x+22))/3#

We can see that #color(blue) ((121x+22))# can be factored.

Finally we get:

#-(11x(11x+2))/3# as our final answer.