How do you solve this? #2/3 + 5/6 = x/2 #

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Answer 1 · 2018-04-13T08:14:51

#x=3#

So I personally like to extend the denominator to get the same denominator. Apply the following:

#2/3 +5/6=x/2#

Extend the #2/3# so we get #4/6#

Now we have:

#4/6 +5/6 =x/2#

#9/6=x/2#

Simplify by dividing by 3 so we get #3/2#

so x=3.

Answer 2 · 2018-04-13T08:16:37

#x = 3#

#2/3+5/6=x/2#

#4/6+5/6=(3x)/6# (Make all of the fractions have a common denominator)

#9/6=(3x)/6# (Simplify the fractions into a single fraction on each side of the equation)

#9 = 3x# (Multiply both sides by #6# and therefore cancelling out the denominator)

#3 = x# (Divide both sides by #3# and thus, getting the answer)

Answer 3 · 2018-04-13T08:20:21

See below.

#2/3 + 5/6=x/2#

#rArr (2xx2)/(3xx2) +5/6=x/2#

Multiply with 2 on both #color(red)(N^r)# and #color(red)(D^r)#

#rArr 4/6+5/6=x/2#

#rArr 9/6=x/2#

Now, cross multiply

#rArr 6x=9xx2#

#rArr x= (3cancel9 xx cancel2)/(cancel2cancel6#

#rArr x=3#

Hope this helps :)