Question

How do you find the perimeter of an isosceles triangle whose base is 16 dm and whose height is 15 dm?

Answer 1

By using the Pythagoras theorem

Explanation:

Draw the triangle first, The height is 15 and base is 16. Cut the triangle in half and you will end up with two triangles with a height of 15 and base of 8. Use the Pythagoras theorem and get the slant height. `a^2=b^2+c^2` By using this equation you will find the slant height
`x^2=15^2+8^2` simplify this and you will get 17 dm. perimeter=17+16+17=50dm