What is the $3sqrt125$ minus $2sqrt80$ plus $sqrt405$ ?

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Answer 1 · 2018-04-14T22:04:55

$16sqrt5$

$3sqrt125-2sqrt80+sqrt405$

$3sqrt(25*5)-2sqrt(16*5)+sqrt(81*5)$

$3*5sqrt5-2*4sqrt5+9sqrt5$

$15sqrt5-8sqrt5+9sqrt5$

$7sqrt5+9sqrt5$

$16sqrt5$

What is the 3sqrt1253sqrt125 minus 2sqrt802sqrt80 plus sqrt405sqrt405?