Find the other dive trigonometric functions OF the acute angle A, given that sec A=2 ?

2 Answers
Apr 15, 2018

Given,secA = 2.
So, cosA = 1/2 = cos 60.
Then, A = 60 degree.
Now, Sin 60 = (sqrt 3)/2,tan 60 = sqrt 3, csc 60 = 2/(sqrt3), cot 60 =1/(sqrt3).

ANOTHER WAY
We know, secA =2/1= (hypotenuse)/(base)
So, height = sqrt[(hypotenuse)^2-(base)^2]
So, height = sqrt[2^2-1^2]
rArr sqrt3

Apr 15, 2018

Given,secA = 2.
So, cosA = 1/2 = cos 60.
Then, A = 60 degree.
Now, Sin 60 = (sqrt 3)/2,tan 60 = sqrt 3, csc 60 = 2/(sqrt3), cot 60 =1/(sqrt3).

ANOTHER WAY
We know, secA =2/1= (hypotenuse)/(base)
So, height = sqrt[(hypotenuse)^2-(base)^2]
So, height = sqrt[2^2-1^2]
rArr sqrt3
Now sinA =(height)/(hypotenuse)=sqrt3/2
CosA= (base)/(hypotenuse)=1/2,
TanA = (height)/(base)=(sqrt3)/1
CscA = 1/sinA =1/[(sqrt3)/2]= 2/(sqrt3),
CotA= 1/tanA =1/(sqrt3)