How do you find the equation of a line tangent to the function #y=x^2-5x+2# at x=3?
2 Answers
Explanation:
Let
At
So, the coordinate is at
We first need to find the slope of the tangent line at the point by differentiating
At
So, the slope of the tangent line there will be
Now, we use the point-slope formula to figure out the equation of the line, that is:
where
And so,
A graph shows us that it's true:
Explanation:
At