Find the value of (7^-1/3)^3 ?

1 Answer
Thomas K.
Apr 15, 2018

#1/7#

Explanation:

Start by getting rid of the negative exponent
To do that you have to flip the problem:
#(1/7^(1/3))^3#
Next multiply the exponent to the parenthesis.
If you cube #1# it just stays #1# and if you cube the #1/3# it cancels because it becomes #3/3#:
#1/7^(3/3)#
Once it becomes #3/3# it simplifies to #1# and #7^1=7#
#1/7#

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