Find the value of (7^-1/3)^3 ?

1 Answer
Apr 15, 2018

1/7

Explanation:

Start by getting rid of the negative exponent
To do that you have to flip the problem:
(1/7^(1/3))^3
Next multiply the exponent to the parenthesis.
If you cube 1 it just stays 1 and if you cube the 1/3 it cancels because it becomes 3/3:
1/7^(3/3)
Once it becomes 3/3 it simplifies to 1 and 7^1=7
1/7