How do you solve for x: 7+ a x = 14- bx?

1 Answer
Apr 15, 2018

x=\frac{7}{a+b}

Explanation:

We have:

7+ax=14-bx

Isolate all the terms that contain x as a factor on the right hand side and move all the other terms to the left hand side:

7+ax=14-bx\implies 7+ax+bx=14

\implies ax+bx=14-7=7

Then, use the common factor x to group the terms:

x(a+b)=7\implies x=\frac{7}{a+b}

Note that this assumes that a+b\ne 0.