Question

How do you solve for `x`: `7+ a x = 14- bx`?

Answer 1

`x=\frac{7}{a+b}`

Explanation:

We have:

`7+ax=14-bx`

Isolate all the terms that contain `x` as a factor on the right hand side and move all the other terms to the left hand side:

`7+ax=14-bx\implies 7+ax+bx=14`

`\implies ax+bx=14-7=7`

Then, use the common factor `x` to group the terms:

`x(a+b)=7\implies x=\frac{7}{a+b}`

Note that this assumes that `a+b\ne 0`.