What is the product of #\frac { 6x } { 4x ^ { 2} - 3x - 1} #and #\frac { 6} { 7x ^ { 2} + 8x + 1}#?

1 Answer
sankarankalyanam
Apr 16, 2018

#=>color(indigo)((6x^2) / ((4x + 1) (x-1) (7x + 1) (x+1))#

Explanation:

#((6x) / (4x^2 -3x -1)) * (6 / (7x^2 + 8x + 1))#

#=> (6x * x) / ((4x^2-3x-1)* (7x^2+8x+1))#

#=> (6x^2) / ((4x^2 -4x +x - 1) * (7x^2 + 7x + x + 1))#

#=> (6x^2) / ((4x (x-1) + (x - 1)) * (7x(x+1) + (x+1))#

#=>(6x^2) / ((4x + 1) (x-1) (7x + 1) (x+1))#

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