Question

Find the value of following by using logarithms? (36.25)*(.003)

Answer 1

`0.10875`

Explanation:

:.Log`36.25=1.559308011`
:.Log`0.003=-2.522878745`

`1.559308011+(-2.522878745)=-0.963570734`

anti log`-0.963570734=0.10875`

(On the calculator type in`-0.963570734` then 2ndF, `10^x` )

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check:- `36.25xx0.003=0.10875`