How do you solve the system of equations #50x + 40= y# and #30x + 45= y#?

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Answer 1 · 2018-04-16T13:00:21

#x=0.25,y=52.5#

#:.50x+40=y------(1)#

#:.30x+45=y------(2)#

#:.(1)-(2)#

#:.20x-5=0#

#:.20x=5#

#:.x=cancel 5^1/cancel 20^4#

#:.x=1/4# or #0.25#

substitute x=0.25 in (1)

#:.50(0.25)+40=y#

#:.12.5+40=y#

#:.y=52.5#

~~~~~~~~~~~~~~~

check:-

substitute #x=0.25#and #y=52.5# in# (2)#

#:.30(0.25)+45=52.5#

#:.7.5+45=52.5#

#:.52.5=52.5#