How do you write the standard form of the equation #y+4=-12/7(x-1)#?

1 Answer
Thomas K.
Apr 16, 2018

#7y+12x=-16#

Explanation:

Standard form is #ay+bx=c#
Start by multiplying everything by #7# to get rid of pesky fraction:
#7y+28=-12(x-1)#
Distribute:
#7y+28=-12x+12#
Than subtract #28# over and add the #12x# over:
#7y+12x=-16#

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