How do you graph using the intercepts for #5x+3y=53#?

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Answer 1 · 2018-04-17T03:54:10

#color(purple)("The two points are " (53/5,0), (0, 53/3)#

#5x + 3y = 53#

#Intercept form of equation is #x / a + y / b = 1#

Converting the given equation to intercept form,

#(5/53) x + (3/53) y = 1#

#x / (53/5) + y / (53/3) =1#

Hence, #"x-intercept " = 53/5, " y-intercept " = 53/3#

#color(purple)("The two points are " (53/5,0), (0, 53/3)#

Now we can plot the graph knowing two points on a line.

graph{-(5/3) x + (53/3) [-10, 10, -5, 5]}